25^(4x-3)=(1/125)^(x+2)

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Solution for 25^(4x-3)=(1/125)^(x+2) equation: 



25^(4x-3)=(1/125)^(x+2)

We move all terms to the left:

25^(4x-3)-((1/125)^(x+2))=0



Domain of the equation: 125)^(x+2))!=0

x∈R



We add all the numbers together, and all the variables

25^(4x-3)-((+1/125)^(x+2))=0

We multiply all the terms by the denominator


(25^(4x-3))*125)^(x+1+2))-((=0

We add all the numbers together, and all the variables

(25^(4x-3))*125)^(x+3))-((=0

We add all the numbers together, and all the variables

(25^(4x-3))*125)^(x=0

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